k = 1;

for (i = 1; i <= 5; i++) k = k + 3 * i;

This code initializes the variable `k` to 1 and then enters a loop that runs 5 times. During each iteration of the loop, the value of `k` is updated by adding 3 times the current value of `i`.

At the end of the loop, the final value of `k` will depend on the value of `i` during the last iteration. In this case, the loop will run for `i = 1, 2, 3, 4, 5`, so the final value of `k` will be:

```
k = 1 + 3*1 + 3*2 + 3*3 + 3*4 + 3*5
k = 1 + 3 + 6 + 9 + 12 + 15
k = 46
```

Therefore, the final value of `k` after the loop is 46.