anastasiya_lykova

First, we can simplify the left side of the equation using the rule that states that the logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator: log6(2x) - log6(2) = log6(2x/2) = log6(x) Substituting this into the original equation, we get: log6(x) = log6(2x-1) Now we can use the fact that if two logarithms with the same base are equal, then their arguments must be equal as well. Therefore, we have: x = 2x - 1 Solving for x, we get: x = 1 Therefore, the solution to the equation is x = 1.