kobachocok

Let's solve the first inequality: $(x+2)(2-x) Expanding both sides: $2x-x^2+4-2x Simplifying: $x^2-x-3 Factorizing: $(x-3)(x+1) The solution is $-1 Now let's solve the second inequality: $45+\frac{x}{3}+\frac{61-2x}{3} \geq 1$ Simplifying: $35+\frac{x}{3} \geq 0$ Multiplying both sides by 3: $x \geq -105$ The solution is $x \geq -105$. Therefore, the solution to the system of inequalities is $-1 < x < 3$ and $x \geq -105$.