Решите систему уравнений методом подстановки \\atop } \\right.\\Rightarrow\\\\\\\\\nx^2+2(x-1)=6\\\\\nx^2+2x-2-6=0\\\\\nx^2+2x-8=0\\\\\nD=4+32=36; \\sqrt=6\\\\\\\\\nx_= \\frac{-2\\pm6}\\\\\\\\\nx_1=-4; \\ x_2=2 [\/tex]<br \/><br \/>\u041f\u0440\u0438 [tex]x=-4[\/tex]:<br \/><br \/>[tex](-4)^2+2y=6\\\\\n2y=6-16\\\\\ny=-10:2\\\\\ny=5\\\\\\\\\n[\/tex]<br \/><br \/>\u041f\u0440\u0438 [tex]x=2[\/tex]<br \/><br \/>[tex]y=2-1\\\\\ny=1[\/tex]<br \/><br \/>\u041f\u0440\u043e\u0432\u0435\u0440\u043a\u0430:<br \/><br \/>[tex]\\left \\{ { \\atop } \\right.\\Rightarrow\\left \\{ {{(-4)^2+2\\cdot(-5)=6} \\atop {-5=(-4)-1}} \\right.\\Rightarrow \\left \\{ { \\atop {-5=-5}} \\right. \\left \\{ { \\atop {-5=-5}} \\right.\\\\\\\\\n \\left \\{ { \\atop } \\right.\\Rightarrow\\left \\{ { \\atop } \\right.\\Rightarrow \\left \\{ { \\atop } \\right. [\/tex]<br \/><br \/>\u041e\u0442\u0432\u0435\u0442: [tex]x_1=-4, y_1=-5;\\ x_2=2, y_2=1[\/tex]"},{"id":12002513,"content":"\u0445\u00b2+2\u0445-2=6<br \/>\u0445\u00b2+2\u0445-8=0<br \/>\u0414=4-4*(-8)=6\u00b2<br \/>\u04451=-2+6\/2=2<br \/>\u04452=-2-6\/2=-4<br \/>\u041f\u0440\u043e\u0438\u0437\u0432\u043e\u0434\u0438\u043c \u043e\u0431\u0440\u0430\u0442\u043d\u0443\u044e \u0437\u0430\u043c\u0435\u043d\u0443, \u043d\u0430\u0445\u043e\u0434\u0438\u043c \u0438\u043a\u0441\u044b.<br \/>\u0443=\u0445-1<br \/>\u04431=\u04451-1=2-1=1<br \/>\u04432=\u04452-1=-4-1=-5<br \/>\u041e\u0442\u0441\u0435\u0432: (2;1) \u0438 (-4;-5)<br \/>"}]" data-testid="answer_box_list">

eugeke eugeke

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Ответ:

Ayreliya Ayreliya

Х²+2х-2=6
х²+2х-8=0
Д=4-4*(-8)=6²
х1=-2+6/2=2
х2=-2-6/2=-4
Производим обратную замену, находим иксы.
у=х-1
у1=х1-1=2-1=1
у2=х2-1=-4-1=-5
Отсев: (2;1) и (-4;-5)